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Dec 27, 2023 at 15:12 history became hot network question
Dec 27, 2023 at 9:14 vote accept user139952
Dec 27, 2023 at 8:48 answer added Fedor Petrov timeline score: 10
Dec 27, 2023 at 8:47 comment added Daniel Weber Using the fact that it can be partitioned I can improve this to $\frac47$
Dec 27, 2023 at 8:38 comment added Daniel Weber A stronger form of the Paley–Zygmund inequality, for example, shows that at least $\frac{4}{13}$ of the subsets have sum of at least $s$.
Dec 27, 2023 at 8:29 comment added Daniel Weber It might be worthwhile to take each element independently with probability $\frac12$ and look at the sum of those variables. Chebyshev's inequality is too weak to yield anything useful, but a Chernoff bound might be useful, I don't have time to try right now.
Dec 27, 2023 at 7:10 history asked user139952 CC BY-SA 4.0