Timeline for Conformal Mappings for hyperbolic polygon
Current License: CC BY-SA 2.5
15 events
| when toggle format | what | by | license | comment | |
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| Oct 7, 2012 at 14:22 | answer | added | Alexandre Eremenko | timeline score: 2 | |
| Aug 9, 2011 at 15:18 | answer | added | Les Virany | timeline score: 0 | |
| Nov 24, 2010 at 15:42 | vote | accept | Marc Palm | ||
| Nov 24, 2010 at 15:42 | vote | accept | Marc Palm | ||
| Nov 24, 2010 at 15:42 | |||||
| Nov 17, 2010 at 13:16 | vote | accept | Marc Palm | ||
| Nov 24, 2010 at 15:42 | |||||
| Nov 17, 2010 at 9:08 | vote | accept | Marc Palm | ||
| Nov 17, 2010 at 13:16 | |||||
| Nov 17, 2010 at 8:24 | vote | accept | Marc Palm | ||
| Nov 17, 2010 at 9:08 | |||||
| Nov 17, 2010 at 8:23 | vote | accept | Marc Palm | ||
| Nov 17, 2010 at 8:23 | |||||
| Nov 16, 2010 at 18:32 | answer | added | SandeepJ | timeline score: 6 | |
| Nov 16, 2010 at 11:44 | history | edited | Marc Palm | CC BY-SA 2.5 |
deleted 125 characters in body; edited tags; edited title
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| Nov 15, 2010 at 17:12 | history | edited | Marc Palm | CC BY-SA 2.5 |
I am searching for explicit construction for conformal mappings for other domains than euclidean polygons
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| Nov 15, 2010 at 8:36 | comment | added | Marc Palm | That is exactly, what I am searching. Thanks Neil for the clarification. | |
| Nov 15, 2010 at 8:32 | comment | added | Neil Strickland | @Adam: a hyperbolic polygon means one whose sides are geodesics for the hyperbolic metric, so they are not usually straight lines. If you take a polygon with straight edges in the upper half plane then the edges are not geodesic for the hyperbolic metric on the upper half plane, and the images in the unit disc are not geodesic for the hyperbolic metric there either. | |
| Nov 15, 2010 at 7:00 | comment | added | Adam Hughes | I'm no expert on the subject, but presumably you could take normal polygons and and map them into the unit disc in the usual way. | |
| Nov 15, 2010 at 6:41 | history | asked | Marc Palm | CC BY-SA 2.5 |