Skip to main content
4 events
when toggle format what by license comment
Nov 15, 2010 at 11:49 comment added Jim Humphreys There is some confusion in the question: an arbitrary parabolic subalgebra is conjugate under the associated adjoint group to a standard one, so all parabolic categories are equivalent to those constructed using some fixed set of simple roots. The choice of simple roots, hence of "standard" parabolics, doesn't matter here.
Nov 15, 2010 at 7:23 comment added Ben Webster I'm having trouble coming up with a clever justification for this argument, but I think that actually, you will just end up with category $\mathcal O$ for the smallest standard parabolic containing whichever one you choose.
Nov 15, 2010 at 1:37 history edited Anton Nazarov CC BY-SA 2.5
Fix spelling and display of mathematical formulae
Nov 15, 2010 at 1:30 history asked Anton Nazarov CC BY-SA 2.5