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Dec 25, 2023 at 3:47 comment added David Gao @NarutakaOZAWA Ah, so the set of all self-adjoint unitaries would be a counterexample. Thank you so much!
Dec 25, 2023 at 2:28 comment added Narutaka OZAWA The same holds for the real case. For example, iid Rademacher variables are orthonormal and hence contain zero in the weak $L^2$ closure.
Dec 22, 2023 at 8:51 history edited David Gao CC BY-SA 4.0
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Dec 22, 2023 at 8:44 comment added David Gao @NarutakaOZAWA You’re right. Guess this isn’t true in general. Do you think a similar counterexample could exist if we also assume all functions in $S$ are real-valued? The unitary example doesn’t seem easily adaptable to that.
Dec 22, 2023 at 8:32 comment added Narutaka OZAWA The set $S$ of unitary functions contains zero in the weak $L^2$ closure.
Dec 22, 2023 at 3:20 history asked David Gao CC BY-SA 4.0