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when toggle format what by license comment
Dec 12, 2023 at 20:21 comment added Joel David Hamkins I think I gave this diagonal argument already in my answer. Namely, for each indexing $\alpha$, we form a 0/1 sequence that when restricted to $\alpha$ does not converge. For example, alternate 0/1 on the values of $\alpha$, and $0$ otherwise. Isn't this the diagonalization you intend?
Dec 12, 2023 at 13:35 history answered terceira CC BY-SA 4.0