Timeline for Lie algebra cohomology of the space of vector fields
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
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| May 19 at 9:20 | comment | added | Qwert Otto | @VladimirDotsenko I thought that substituting $B^e = A$ and pulling back by $\mathrm{Der}(B)\to \mathrm{Der}(A)$ recovers enough information for my computation, but you're right. I should've taken $A^e/[A^e,A^e]$ for better formulation. Thanks. | |
| May 19 at 8:51 | comment | added | Vladimir Dotsenko | I am a bit surprised that you take $A/[A,A]$ as coefficients - at least if you want to imitate the divergence statement, since the conceptually meaningful divergence of a derivation takes values in the commutator quotient of the universal enveloping algebra, not in the commutator quotient of the algebra itself. | |
| S Jan 15 at 16:04 | history | bounty ended | CommunityBot | ||
| S Jan 15 at 16:04 | history | notice removed | CommunityBot | ||
| Jan 7 at 15:14 | history | edited | Qwert Otto |
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| S Jan 7 at 14:15 | history | bounty started | Qwert Otto | ||
| S Jan 7 at 14:15 | history | notice added | Qwert Otto | Draw attention | |
| Jan 7 at 14:13 | history | edited | Qwert Otto | CC BY-SA 4.0 |
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| Dec 12, 2023 at 2:49 | history | edited | Qwert Otto | CC BY-SA 4.0 |
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| Dec 11, 2023 at 10:53 | history | edited | Qwert Otto | CC BY-SA 4.0 |
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| Dec 11, 2023 at 10:53 | comment | added | Qwert Otto | @YCor Thanks for the comment. Some assumptions are added. | |
| Dec 11, 2023 at 10:27 | comment | added | YCor | It's not true for $A=\{0\}$, since the left-hand term is zero and the right-hand term is not (because of $\oplus K$). You might also compare with the case of $M$ with $n$ connected components, which corresponds to $A$ being a product of $n$ indecomposable commutative algebras. | |
| Dec 11, 2023 at 8:49 | history | asked | Qwert Otto | CC BY-SA 4.0 |