Timeline for Conformal Killing vector fields on manifolds that are not asymptotically flat
Current License: CC BY-SA 4.0
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Dec 11, 2023 at 5:47 | history | edited | Laithy | CC BY-SA 4.0 |
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Dec 10, 2023 at 4:20 | comment | added | Laithy | The idea is that if you a priori know that your vector field $X$ goes to $0$ as $r$ goes to $\infty$, then $X$ is conformal Killing implies that it's the $0$ vector field. Check the footnote in pg 324. | |
Dec 9, 2023 at 14:42 | comment | added | Tim Carson | I'm confused by the argument for the case when $g$ is asymptotically flat. It appears in the cited paper as: "On an asymptotically flat manifold $Z^a$ must approach one must approach asymptotically one of the familiar translation or rotation Killing vectors of Euclidean space." How do we know that the limit is a non-zero Killing vector field? Indeed, isn't that what we're trying to prove? | |
Dec 9, 2023 at 0:20 | history | asked | Laithy | CC BY-SA 4.0 |