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Dec 19, 2023 at 8:43 vote accept renphysics
Dec 6, 2023 at 14:18 answer added Alexandre Eremenko timeline score: 2
Dec 5, 2023 at 19:40 comment added Christian Remling Since the potential $V(x)=2q\cosh 2x$ satisfies $\lim_{x\to\pm\infty}V(x)=\infty$, the spectrum is indeed purely discrete and the eigenvalues are positive since $V>0$. I cannot see any reason to expect that these can be found explicitly.
Dec 5, 2023 at 11:05 history asked renphysics CC BY-SA 4.0