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Dec 5, 2023 at 3:01 comment added user8469759 I more meant "quadratic energies" not "quadratic forms". So something like $E(\alpha f) = \left| \alpha \right| ^2 E(f)$. Also in $\Delta f = 0$ I more meant the operator $\Delta$. I also think I meant if there's a general theorem between energies and selfadjoint operators (not necessarily quadratic).
Dec 4, 2023 at 15:38 comment added Christian Remling Yes, one can obtain self-adjoint operators from quadratic forms, and it's a standard method. (Of course, there's no minimization to produce the operator, but that's just as well since $\Delta f=0$ is an equation, not an operator.)
Dec 4, 2023 at 11:53 history edited Hannes CC BY-SA 4.0
typo in definition of E
Dec 4, 2023 at 7:27 history edited YCor CC BY-SA 4.0
removed capitals from title, removed meta tag
Dec 4, 2023 at 2:55 history asked user8469759 CC BY-SA 4.0