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Martin Brandenburg
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This is section 5.1 from, ARITHMETIC DERIVATIVES THROUGH GEOMETRY OF NUMBERS by Hector Pasten.

Let $A$ be a commutative unitary ring, let $R$ be a commutative monoid, and let $\alpha : R \to A$ be a morphism of monoids with $A$ taken as a multiplicative monoid. Given an $A$-module $U$, a $U$-valued $\alpha$-derivation on $A$ is a function $D : A \to U$ satisfying

  1. (Diff1) $R$-triviality: $D(\alpha(r)) = 0$ for all $r ∈ R$;
  2. (Diff2) Leibniz rule: $D(ab) = a \, D(b) + b \, D(a)$ for all $a, b ∈ A$. A differential $(A, \alpha)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $\alpha$-derivation on $A$.

A differential $(A, \alpha)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $\alpha$-derivation on $A$.

Given differential $(A, \alpha)$-modules $(U, D)$ and $(V, E)$, a morphism of differential $(A, \alpha)$-modules is a morphism of $A$-modules $f : U \rightarrow V$ that satisfies $E = f \circ D$. We obtain a category of differential $(A, \alpha)$-modules which we denote by $Φ(A,\alpha)$.

For an $A$-module $U$, let $Der(A,\alpha)(U) = \{D : A \to U : (U, D) \in Ob(Φ(A,\alpha))\}$.$$Der(A,\alpha)(U) = \{D : A \to U : (U,D) \in Ob(Φ(A,\alpha))\}.$$ This is an $A$-module with the structure induced by $U$. Given $A$-modules $U$ and $V$ and a morphism $f \in Hom_A(U, V)$, we define $Der(A,\alpha)(f) : Der(A,\alpha)(U) \to Der(A,\alpha)(V)$$$Der(A,\alpha)(f) : Der(A,\alpha)(U) \to Der(A,\alpha)(V)$$ by $Der(A,\alpha)(f)(D) = f \circ D$.

Lemma 5.2. The rule $Der(A,\alpha)$ defines a functor $A{-}\mathbf{Mod} \rightarrow A{-}\mathbf{Mod}$.

The lemma 5.2 is provided without a proof.

I am left to wonder how is this map on objects defined given an $A$-module $U$, I cant see how to read the set builder style notation for objects in a way that makes sense to me. How should one read it?

To note some of the confusing bits about this section: $D, E$ are functions, $f$ is a morphism of $A$-modules their composition is a morphism of $A$-modules, I understand how this yields another function. Are morphism of $A$-modules post-composed with functions again sensible morphisms of $A$-modules in some way?

This is section 5.1 from, ARITHMETIC DERIVATIVES THROUGH GEOMETRY OF NUMBERS by Hector Pasten.

Let $A$ be a commutative unitary ring, let $R$ be a commutative monoid, and let $\alpha : R \to A$ be a morphism of monoids with $A$ taken as a multiplicative monoid. Given an $A$-module $U$, a $U$-valued $\alpha$-derivation on $A$ is a function $D : A \to U$ satisfying

  1. (Diff1) $R$-triviality: $D(\alpha(r)) = 0$ for all $r ∈ R$;
  2. (Diff2) Leibniz rule: $D(ab) = a \, D(b) + b \, D(a)$ for all $a, b ∈ A$. A differential $(A, \alpha)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $\alpha$-derivation on $A$.

A differential $(A, \alpha)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $\alpha$-derivation on $A$.

Given differential $(A, \alpha)$-modules $(U, D)$ and $(V, E)$, a morphism of differential $(A, \alpha)$-modules is a morphism of $A$-modules $f : U \rightarrow V$ that satisfies $E = f \circ D$. We obtain a category of differential $(A, \alpha)$-modules which we denote by $Φ(A,\alpha)$.

For an $A$-module $U$, let $Der(A,\alpha)(U) = \{D : A \to U : (U, D) \in Ob(Φ(A,\alpha))\}$. This is an $A$-module with the structure induced by $U$. Given $A$-modules $U$ and $V$ and a morphism $f \in Hom_A(U, V)$, we define $Der(A,\alpha)(f) : Der(A,\alpha)(U) \to Der(A,\alpha)(V)$ by $Der(A,\alpha)(f)(D) = f \circ D$.

Lemma 5.2. The rule $Der(A,\alpha)$ defines a functor $A{-}\mathbf{Mod} \rightarrow A{-}\mathbf{Mod}$.

The lemma 5.2 is provided without a proof.

I am left to wonder how is this map on objects defined given an $A$-module $U$, I cant see how to read the set builder style notation for objects in a way that makes sense to me. How should one read it?

To note some of the confusing bits about this section: $D, E$ are functions, $f$ is a morphism of $A$-modules their composition is a morphism of $A$-modules, I understand how this yields another function. Are morphism of $A$-modules post-composed with functions again sensible morphisms of $A$-modules in some way?

This is section 5.1 from, ARITHMETIC DERIVATIVES THROUGH GEOMETRY OF NUMBERS by Hector Pasten.

Let $A$ be a commutative unitary ring, let $R$ be a commutative monoid, and let $\alpha : R \to A$ be a morphism of monoids with $A$ taken as a multiplicative monoid. Given an $A$-module $U$, a $U$-valued $\alpha$-derivation on $A$ is a function $D : A \to U$ satisfying

  1. (Diff1) $R$-triviality: $D(\alpha(r)) = 0$ for all $r ∈ R$;
  2. (Diff2) Leibniz rule: $D(ab) = a \, D(b) + b \, D(a)$ for all $a, b ∈ A$. A differential $(A, \alpha)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $\alpha$-derivation on $A$.

A differential $(A, \alpha)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $\alpha$-derivation on $A$.

Given differential $(A, \alpha)$-modules $(U, D)$ and $(V, E)$, a morphism of differential $(A, \alpha)$-modules is a morphism of $A$-modules $f : U \rightarrow V$ that satisfies $E = f \circ D$. We obtain a category of differential $(A, \alpha)$-modules which we denote by $Φ(A,\alpha)$.

For an $A$-module $U$, let $$Der(A,\alpha)(U) = \{D : A \to U : (U,D) \in Ob(Φ(A,\alpha))\}.$$ This is an $A$-module with the structure induced by $U$. Given $A$-modules $U$ and $V$ and a morphism $f \in Hom_A(U, V)$, we define $$Der(A,\alpha)(f) : Der(A,\alpha)(U) \to Der(A,\alpha)(V)$$ by $Der(A,\alpha)(f)(D) = f \circ D$.

Lemma 5.2. The rule $Der(A,\alpha)$ defines a functor $A{-}\mathbf{Mod} \rightarrow A{-}\mathbf{Mod}$.

The lemma 5.2 is provided without a proof.

I am left to wonder how is this map on objects defined given an $A$-module $U$, I cant see how to read the set builder style notation for objects in a way that makes sense to me. How should one read it?

To note some of the confusing bits about this section: $D, E$ are functions, $f$ is a morphism of $A$-modules their composition is a morphism of $A$-modules, I understand how this yields another function. Are morphism of $A$-modules post-composed with functions again sensible morphisms of $A$-modules in some way?

edited tags
Source Link
Martin Brandenburg
  • 63.1k
  • 13
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  • 424

This is section 5.1 from, ARITHMETIC DERIVATIVES THROUGH GEOMETRY OF NUMBERS by Hector Pasten.

Let $A$ be a commutative unitary ring, let $R$ be a commutative monoid, and let $α ∶ R → A$$\alpha : R \to A$ be a morphism of monoids with A$A$ taken as a multiplicative monoid. Given an $A$-module $U$, a $U$-valued α$\alpha$-derivation on $A$ is a function $D ∶ A → U$$D : A \to U$ satisfying

  1. (Diff1) $R$-triviality: $D(α(r)) = 0$$D(\alpha(r)) = 0$ for all $r ∈ R$;
  2. (Diff2) Leibniz rule: $D(ab) = a \, D(b) + b \, D(a)$ for all $a, b ∈ A$. A differential $(A, α)$$(A, \alpha)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $α$$\alpha$-derivation on $A$.

A differential $(A, α)$$(A, \alpha)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $α$$\alpha$-derivation on $A$.

Given differential $(A, α)$$(A, \alpha)$-modules $(U, D)$ and $(V, E)$, a morphism of differential $(A, α)$$(A, \alpha)$-modules is a morphism of $A$-modules $f : U \rightarrow V$ that satisfies $E = f \circ D$. We obtain a category of differential $(A, α)$$(A, \alpha)$-modules which we denote by $Φ(A,α)$$Φ(A,\alpha)$.

For an $A$-module $U$, let $Der(A,α)(U) = \{D : A \to U : (U, D) \in Ob(Φ(A,α))\}$$Der(A,\alpha)(U) = \{D : A \to U : (U, D) \in Ob(Φ(A,\alpha))\}$. This is an $A$-module with the structure induced by $U$. Given $A$-modules $U$ and $V$ and a morphism $f \in Hom_A(U, V)$, we define $Der(A,α)(f) : Der(A,α)(U) \to Der(A,α)(V)$$Der(A,\alpha)(f) : Der(A,\alpha)(U) \to Der(A,\alpha)(V)$ by $Der(A,α)(f)(D) = f \circ D$$Der(A,\alpha)(f)(D) = f \circ D$.

Lemma 5.2. The rule $Der(A,α)$$Der(A,\alpha)$ defines a functor $A$-Mod $\rightarrow$ $A$-Mod$A{-}\mathbf{Mod} \rightarrow A{-}\mathbf{Mod}$.

The lemma 5.2 is provided without a proof.

I am left to wonder how is this map on objects defined given an $A$-module $U$, I cant see how to read the set builder style notation for objects in a way that makes sense to me. How should one read it?

To note some of the confusing bits about this section: $D, E$ are functions, $f$ is a morphism of $A$-modules their composition is a morphism of $A$-modules, I understand how this yields another function. Are morphism of $A$-modules post-composed with functions again sensible morphisms of $A$-modules in some way?

This is section 5.1 from, ARITHMETIC DERIVATIVES THROUGH GEOMETRY OF NUMBERS by Hector Pasten.

Let $A$ be a commutative unitary ring, let $R$ be a commutative monoid, and let $α ∶ R → A$ be a morphism of monoids with A taken as a multiplicative monoid. Given an $A$-module $U$, a $U$-valued α-derivation on $A$ is a function $D ∶ A → U$ satisfying

  1. (Diff1) $R$-triviality: $D(α(r)) = 0$ for all $r ∈ R$;
  2. (Diff2) Leibniz rule: $D(ab) = a \, D(b) + b \, D(a)$ for all $a, b ∈ A$. A differential $(A, α)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $α$-derivation on $A$.

A differential $(A, α)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $α$-derivation on $A$.

Given differential $(A, α)$-modules $(U, D)$ and $(V, E)$, a morphism of differential $(A, α)$-modules is a morphism of $A$-modules $f : U \rightarrow V$ that satisfies $E = f \circ D$. We obtain a category of differential $(A, α)$-modules which we denote by $Φ(A,α)$.

For an $A$-module $U$, let $Der(A,α)(U) = \{D : A \to U : (U, D) \in Ob(Φ(A,α))\}$. This is an $A$-module with the structure induced by $U$. Given $A$-modules $U$ and $V$ and a morphism $f \in Hom_A(U, V)$, we define $Der(A,α)(f) : Der(A,α)(U) \to Der(A,α)(V)$ by $Der(A,α)(f)(D) = f \circ D$.

Lemma 5.2. The rule $Der(A,α)$ defines a functor $A$-Mod $\rightarrow$ $A$-Mod

The lemma 5.2 is provided without a proof.

I am left to wonder how is this map on objects defined given an $A$-module $U$, I cant see how to read the set builder style notation for objects in a way that makes sense to me. How should one read it?

To note some of the confusing bits about this section: $D, E$ are functions, $f$ is a morphism of $A$-modules their composition is a morphism of $A$-modules, I understand how this yields another function. Are morphism of $A$-modules post-composed with functions again sensible morphisms of $A$-modules in some way?

This is section 5.1 from, ARITHMETIC DERIVATIVES THROUGH GEOMETRY OF NUMBERS by Hector Pasten.

Let $A$ be a commutative unitary ring, let $R$ be a commutative monoid, and let $\alpha : R \to A$ be a morphism of monoids with $A$ taken as a multiplicative monoid. Given an $A$-module $U$, a $U$-valued $\alpha$-derivation on $A$ is a function $D : A \to U$ satisfying

  1. (Diff1) $R$-triviality: $D(\alpha(r)) = 0$ for all $r ∈ R$;
  2. (Diff2) Leibniz rule: $D(ab) = a \, D(b) + b \, D(a)$ for all $a, b ∈ A$. A differential $(A, \alpha)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $\alpha$-derivation on $A$.

A differential $(A, \alpha)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $\alpha$-derivation on $A$.

Given differential $(A, \alpha)$-modules $(U, D)$ and $(V, E)$, a morphism of differential $(A, \alpha)$-modules is a morphism of $A$-modules $f : U \rightarrow V$ that satisfies $E = f \circ D$. We obtain a category of differential $(A, \alpha)$-modules which we denote by $Φ(A,\alpha)$.

For an $A$-module $U$, let $Der(A,\alpha)(U) = \{D : A \to U : (U, D) \in Ob(Φ(A,\alpha))\}$. This is an $A$-module with the structure induced by $U$. Given $A$-modules $U$ and $V$ and a morphism $f \in Hom_A(U, V)$, we define $Der(A,\alpha)(f) : Der(A,\alpha)(U) \to Der(A,\alpha)(V)$ by $Der(A,\alpha)(f)(D) = f \circ D$.

Lemma 5.2. The rule $Der(A,\alpha)$ defines a functor $A{-}\mathbf{Mod} \rightarrow A{-}\mathbf{Mod}$.

The lemma 5.2 is provided without a proof.

I am left to wonder how is this map on objects defined given an $A$-module $U$, I cant see how to read the set builder style notation for objects in a way that makes sense to me. How should one read it?

To note some of the confusing bits about this section: $D, E$ are functions, $f$ is a morphism of $A$-modules their composition is a morphism of $A$-modules, I understand how this yields another function. Are morphism of $A$-modules post-composed with functions again sensible morphisms of $A$-modules in some way?

edited tags
Source Link
Martin Brandenburg
  • 63.1k
  • 13
  • 207
  • 424

This is section 5.1 from, ARITHMETIC DERIVATIVES THROUGH GEOMETRY OF NUMBERS by Hector Pasten.

Let $A$ be a commutative unitary ring, let $R$ be a commutative monoid, and let $α ∶ R → A$ be a morphism of monoids with A taken as a multiplicative monoid. Given an $A$-  module $U$, a $U$-valued α-derivation on A$A$ is a function $D ∶ A → U$ satisfying

  1. (Diff1) R$R$-triviality: $D(α(r)) = 0$ for all $r ∈ R$;
  2. (Diff2) Leibniz rule: $D(ab) = aD(b) + bD(a)$$D(ab) = a \, D(b) + b \, D(a)$ for all $a, b ∈ A$. A differential $(A, α)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $α$-derivation on $A$.

A differential $(A, α)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $α$-derivation on $A$.

Given differential $(A, α)$-modules $(U, D)$ and $(V, E)$, a morphism of differential $(A, α)$-modules is a morphism of $A$-modules $f : U \rightarrow V$ that satisfies $E = f ◦ D$$E = f \circ D$. We obtain a category of differential $(A, α)$-modules which we denote by $Φ(A,α)$.

For an A$A$-module U $U$, let $Der(A,α)(U) = \{D : A → U : (U, D) ∈ Ob(Φ(A,α))\}$$Der(A,α)(U) = \{D : A \to U : (U, D) \in Ob(Φ(A,α))\}$. This is an A$A$-module with the structure induced by U$U$. Given A$A$-modules U$U$ and V$V$ and a morphism f ∈ HomA(U, V)$f \in Hom_A(U, V)$, we define $Der(A,α)(f) : Der(A,α)(U) → Der(A,α)(V)$$Der(A,α)(f) : Der(A,α)(U) \to Der(A,α)(V)$ by $Der(A,α)(f)(D) = f ◦ D$$Der(A,α)(f)(D) = f \circ D$.

Lemma 5.2. The rule $Der(A,α)$ defines a functor $A$-Mod $\rightarrow$ $A$-Mod

The lemma 5.2 is provided without a proof.

I am left to wonder how is this map on objects defined given an A$A$-Module Umodule $U$, I cant see how to read the set builder style notation for objects in a way that makes sense to me. How should one read it?

To note some of the confusing bits about this section: D, E$D, E$ are functions, f$f$ is a morphism of A$A$-modules their composition is a morphism of A$A$-modules, I understand how this yields another function. Are morphism of A$A$-modules post-composed with functions again sensible morphisms of A$A$-modules in some way?

This is section 5.1 from, ARITHMETIC DERIVATIVES THROUGH GEOMETRY OF NUMBERS by Hector Pasten.

Let $A$ be a commutative unitary ring, let $R$ be a commutative monoid, and let $α ∶ R → A$ be a morphism of monoids with A taken as a multiplicative monoid. Given an $A$-  module $U$, a $U$-valued α-derivation on A is a function $D ∶ A → U$ satisfying

  1. (Diff1) R-triviality: $D(α(r)) = 0$ for all $r ∈ R$;
  2. (Diff2) Leibniz rule: $D(ab) = aD(b) + bD(a)$ for all $a, b ∈ A$. A differential $(A, α)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $α$-derivation on $A$.

A differential $(A, α)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $α$-derivation on $A$.

Given differential $(A, α)$-modules $(U, D)$ and $(V, E)$, a morphism of differential $(A, α)$-modules is a morphism of $A$-modules $f : U \rightarrow V$ that satisfies $E = f ◦ D$. We obtain a category of differential $(A, α)$-modules which we denote by $Φ(A,α)$.

For an A-module U , let $Der(A,α)(U) = \{D : A → U : (U, D) ∈ Ob(Φ(A,α))\}$. This is an A-module with the structure induced by U. Given A-modules U and V and a morphism f ∈ HomA(U, V), we define $Der(A,α)(f) : Der(A,α)(U) → Der(A,α)(V)$ by $Der(A,α)(f)(D) = f ◦ D$.

Lemma 5.2. The rule $Der(A,α)$ defines a functor $A$-Mod $\rightarrow$ $A$-Mod

The lemma 5.2 is provided without a proof.

I am left to wonder how is this map on objects defined given an A-Module U, I cant see how to read the set builder style notation for objects in a way that makes sense to me. How should one read it?

To note some of the confusing bits about this section: D, E are functions, f is a morphism of A-modules their composition is a morphism of A-modules, I understand how this yields another function. Are morphism of A-modules post-composed with functions again sensible morphisms of A-modules in some way?

This is section 5.1 from, ARITHMETIC DERIVATIVES THROUGH GEOMETRY OF NUMBERS by Hector Pasten.

Let $A$ be a commutative unitary ring, let $R$ be a commutative monoid, and let $α ∶ R → A$ be a morphism of monoids with A taken as a multiplicative monoid. Given an $A$-module $U$, a $U$-valued α-derivation on $A$ is a function $D ∶ A → U$ satisfying

  1. (Diff1) $R$-triviality: $D(α(r)) = 0$ for all $r ∈ R$;
  2. (Diff2) Leibniz rule: $D(ab) = a \, D(b) + b \, D(a)$ for all $a, b ∈ A$. A differential $(A, α)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $α$-derivation on $A$.

A differential $(A, α)$-module is a pair $(U , D)$, where $U$ is an $A$-module and $D$ is a $U$-valued $α$-derivation on $A$.

Given differential $(A, α)$-modules $(U, D)$ and $(V, E)$, a morphism of differential $(A, α)$-modules is a morphism of $A$-modules $f : U \rightarrow V$ that satisfies $E = f \circ D$. We obtain a category of differential $(A, α)$-modules which we denote by $Φ(A,α)$.

For an $A$-module $U$, let $Der(A,α)(U) = \{D : A \to U : (U, D) \in Ob(Φ(A,α))\}$. This is an $A$-module with the structure induced by $U$. Given $A$-modules $U$ and $V$ and a morphism $f \in Hom_A(U, V)$, we define $Der(A,α)(f) : Der(A,α)(U) \to Der(A,α)(V)$ by $Der(A,α)(f)(D) = f \circ D$.

Lemma 5.2. The rule $Der(A,α)$ defines a functor $A$-Mod $\rightarrow$ $A$-Mod

The lemma 5.2 is provided without a proof.

I am left to wonder how is this map on objects defined given an $A$-module $U$, I cant see how to read the set builder style notation for objects in a way that makes sense to me. How should one read it?

To note some of the confusing bits about this section: $D, E$ are functions, $f$ is a morphism of $A$-modules their composition is a morphism of $A$-modules, I understand how this yields another function. Are morphism of $A$-modules post-composed with functions again sensible morphisms of $A$-modules in some way?

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