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Nov 30, 2023 at 9:24 history edited Leo Alonso CC BY-SA 4.0
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Nov 29, 2023 at 19:13 comment added Leo Alonso Basically you take a Noether normalization $X \to P^1 \to \operatorname{Spec}(k)$ and then they integral on $X$ is the composition of the trace from $X$ to $P^1$ and the integral on $P^1$ that you can compute with Czech cocycles.
Nov 29, 2023 at 17:44 vote accept Emiliano Ambrosi
Nov 29, 2023 at 17:44 comment added Emiliano Ambrosi I have just one further question: do you know how does the map H^1(X,\Omega^1_{X/k})---> k looks in some concrete situation? For example, I can image what is it if X is the union of two P^1, but I can't guess what the map does if X is a double line for example (i.e. x^2=0 inside P^2). Is it the composition of the map to the reduced part and the trace of this one?
Nov 29, 2023 at 17:41 comment added Emiliano Ambrosi Thank you very much, this is exactly what I was looking for!
Nov 29, 2023 at 12:56 history answered Leo Alonso CC BY-SA 4.0