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Jan 7 at 14:59 vote accept user103464
Nov 29, 2023 at 21:14 answer added David E Speyer timeline score: 3
Nov 29, 2023 at 16:00 comment added user103464 Thanks a lot for fixing the Latex, somehow it wasn't displaying properly on my laptop so I removed it. So just restating what you said @fedja: there exists a set of vectors that are at pairwise distance $\sqrt 2 \pm O(1/d)$ but such that for any set of $d$ pairwise orthogonal vectors, there is one of the input vector at distance $O(1/\sqrt d)$?
Nov 29, 2023 at 15:43 comment added kodlu @fedja, thanks; You're right for normalized vectors the Welch lower bound gives the bound stated in your comment.
Nov 29, 2023 at 15:39 comment added fedja @kodlu I fixed the $\LaTeX$ :-)
Nov 29, 2023 at 15:38 history edited fedja CC BY-SA 4.0
added 31 characters in body
Nov 29, 2023 at 15:35 comment added fedja "such that each point of $S$ is mapped to a point in $Q$ at distance at most $O(1/d)$" That is too much to ask for. You cannot hope for a better bound than $O(1/\sqrt d)$ here.
Nov 29, 2023 at 13:16 comment added kodlu Please use MathJax for your equations
Nov 29, 2023 at 4:21 history asked user103464 CC BY-SA 4.0