Timeline for Is "the purely probabilistic version of Freiling's axiom of symmetry" disprovable in ZFC?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 4, 2023 at 16:56 | answer | added | Elliot Glazer | timeline score: 3 | |
| Nov 27, 2023 at 21:03 | history | became hot network question | |||
| Nov 27, 2023 at 14:18 | vote | accept | Julian Newman | ||
| Nov 27, 2023 at 13:53 | answer | added | Gro-Tsen | timeline score: 9 | |
| Nov 27, 2023 at 13:42 | comment | added | Gro-Tsen | Related to “what forms of Fubini are consistent with ZFC”: this other question I asked a few months ago, and this paper by Harvey Friedman on “A Consistent Fubini-Tonelli Theorem”. | |
| Nov 27, 2023 at 13:32 | answer | added | Joel David Hamkins | timeline score: 7 | |
| Nov 27, 2023 at 13:12 | history | edited | Asaf Karagila♦ |
edited tags
|
|
| Nov 27, 2023 at 13:03 | comment | added | Joel David Hamkins | @JosephVanName $S$ may not be measurable, even if its sections are, so Fubini does not apply. For example, under CH there is such a set, the graph of a well order, which has countable sections one way and co-countable the other. This realizes the case $c=1$ under CH. | |
| Nov 27, 2023 at 12:59 | history | asked | Julian Newman | CC BY-SA 4.0 |