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S Dec 6, 2023 at 14:06 history bounty ended CommunityBot
S Dec 6, 2023 at 14:06 history notice removed CommunityBot
Nov 30, 2023 at 8:16 answer added Sebastian timeline score: 4
Nov 28, 2023 at 12:56 history edited Sebastian
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S Nov 28, 2023 at 12:56 history bounty started Sebastian
S Nov 28, 2023 at 12:56 history notice added Sebastian Draw attention
Nov 27, 2023 at 6:47 comment added Sebastian I want the Riemann surface to be compact (otherwise, the above definition of gonality does not make sense). I therefore add these points, in the analogous way you do add two points for hyperelliptic curve determined by the algebraic equation $y^2=(z-z_1)\dots (z-z_{2g+2})$. Note that these curves are (in general) not smooth in $\mathbb CP^2$, as their genus $g=(k-1)(l-1)$ is quite arbitrary.
Nov 27, 2023 at 5:44 comment added Daniel Asimov Is that because you want your surfaces to be projective, i.e., complex submanifolds of ℂℙ^2. or something else?
Nov 27, 2023 at 1:24 comment added Sebastian Of course, the equations define a complex 1-dimensional submanifold in $\mathbb C^2$, but then you add some points ($k$ many over $v=\infty$ and $l$ many over $u=\infty$) to obtain the compact Riemann surface $\Sigma_{k,l}$.
Nov 26, 2023 at 18:43 comment added Daniel Asimov Your algebraic equation appears to define your surface 𝜮_𝒌,𝒍 as a submanifold of ℂ^2. Is that right?
Nov 26, 2023 at 10:58 history asked Sebastian CC BY-SA 4.0