Skip to main content
3 events
when toggle format what by license comment
Nov 24, 2023 at 7:56 comment added newbie Thanks, that was simpler than I thought. I got confused as previous theorems required $f \in \mathcal{S}'$ for the lower inequality, and as such we needed the Fourier transform of the difference to be supported at $\{0\},$ whereas here $f \in \mathcal{S}$ so no such trickery is required.
Nov 24, 2023 at 7:54 vote accept newbie
Nov 23, 2023 at 19:51 history answered Ben Johnsrude CC BY-SA 4.0