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Nov 20, 2023 at 3:09 comment added Farmer S The pointwise definability is because the theory includes "$V=L$" + KP. Given any model $M$ of "$V=L$" plus some basic set theory included in KP, the definable hull of $M$ (the collection of elements of $M$ definable over $M$) is elementary in $M$ and is pointwise definable. For the second point, it can be seen in Theorem 4F.1 in Moschovakis "Descriptive set theory", 2nd ed.
Nov 19, 2023 at 19:52 comment added Hanul Jeon Thank you for your interesting answer, and let me ask a question about the facts in your argument. You used the two facts "Every $T\in X$ has a pointwise definable model" and "If $A$ is $\Sigma^1_1$ and $A\nsubseteq L_{\omega_1^{CK}}$ then $A$ has a perfect subset." Is there any reference for these facts?
Nov 19, 2023 at 5:35 vote accept Hanul Jeon
Nov 19, 2023 at 2:08 history edited Farmer S CC BY-SA 4.0
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Nov 19, 2023 at 2:02 history answered Farmer S CC BY-SA 4.0