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Timeline for Generalization of category algebra

Current License: CC BY-SA 4.0

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Oct 5 at 0:27 vote accept Hang
Sep 26 at 2:22 comment added Hang Thanks for your answer again. I was wondering if the following idea might work, and would greatly appreciate your comment: First, we take the free module generated by the set of all multi-morphisms, denoted by F. But, F may be too large to have an unambiguous product. So, a naive approach is simply taking the quotient of F with respect to the following equivalent relation: we say two multi-morphisms are equivalent if they are compositions of the same set of multimorphisms, differing only in the positions where the compositions occur. But, I am not sure if this is well-defined.
Sep 23 at 5:12 vote accept Hang
Oct 5 at 0:26
Nov 19, 2023 at 0:35 comment added Kevin Carlson @Hang I guess. It’s not a very natural condition on a multicategory. Better to let the object you’re studying guide the construction rather than the other way around, I think.
Nov 18, 2023 at 18:57 comment added Hang Thank you! Probably, we should assume the domains of multimorphisms are all different (in particular, we may exclude $(a, a)$ as you mentioned). Then, we may likely make it into an $R$-algebra, I guess.
Nov 18, 2023 at 0:05 history answered Kevin Carlson CC BY-SA 4.0