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Nov 20, 2023 at 11:16 vote accept Pène Papin
Nov 18, 2023 at 6:48 comment added Ariyan Javanpeykar Yes, that’s right.
Nov 17, 2023 at 22:01 comment added Kevin Casto So in the general case (say if you cannot find a $\mathbb Q$-rational point), you just have to find a number field $K$ where $X$ has a smooth point, and then you are reduced to showing that $X$ is irreducible over $K$ -- is that right?
S Nov 17, 2023 at 13:33 history suggested John Doyle CC BY-SA 4.0
Minor edits
Nov 17, 2023 at 13:09 review Suggested edits
S Nov 17, 2023 at 13:33
Nov 17, 2023 at 12:04 history answered Ariyan Javanpeykar CC BY-SA 4.0