Timeline for On 'special' points on uniform planar convex regions defined in terms of moment of inertia
Current License: CC BY-SA 4.0
13 events
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| Nov 22, 2023 at 22:51 | comment | added | Iosif Pinelis | @NandakumarR : I see your point. Will have this in mind. | |
| Nov 22, 2023 at 11:47 | comment | added | Nandakumar R | Thanks. Even the circumcenter, say, of a triangle could be outside so one suspects this 'really special' point (if unique) could be another center, maybe always coincident with some better known center. | |
| Nov 19, 2023 at 14:57 | comment | added | Iosif Pinelis | @NandakumarR : I think that if, instead of the narrow rectangle, you take a narrow triangle, then the "really special" points will be outside the triangle, just as they are for narrow rectangles. | |
| Nov 19, 2023 at 4:05 | vote | accept | Nandakumar R | ||
| Nov 19, 2023 at 4:05 | comment | added | Nandakumar R | Thank you. I understand that any point P on the plane of C has either 2 mutually perpendicular lines thru P for which C has equal moment of inertia or infinitely many lines thru P for which C has equal MI (no 'in between' points). in the special case when C is a triangle, there might be only one 'really special' point on the plane. If so, is this special point the same as any known center of the triangle? it appears: arguments above, including the lemma (holds for any point on the plane of C, not only in its interior) depend on the moment being MI and not any other moment. | |
| Nov 19, 2023 at 1:13 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Nov 17, 2023 at 14:00 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Nov 17, 2023 at 13:52 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Nov 17, 2023 at 4:55 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Nov 16, 2023 at 22:55 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |