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Nov 28, 2023 at 6:30 comment added Sungwoo @AGlearner I am sorry for the confusion. What I meant is fibers of the map $S\to \mathbb{P}^1$, not fibers of $K_S$. So I am contracting a family of $\mathbb{P}^1$s in X.
Nov 28, 2023 at 6:28 history edited Sungwoo CC BY-SA 4.0
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Nov 21, 2023 at 19:12 comment added AG learner What is the contraction $X\to Y$? You said "collapsing all the fibers of $S$". This implies $Y=S$, but I don't think this is what you meant.
Nov 16, 2023 at 6:02 history asked Sungwoo CC BY-SA 4.0