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Dec 15, 2023 at 3:38 vote accept Neil Strickland
Nov 13, 2023 at 7:24 comment added Maxime Ramzi Your answer looks perfectly fine :)
Nov 12, 2023 at 20:17 comment added Neil Strickland @MaximeRamzi I think that you are right. I have entered my own answer along those lines, but if you prefer to enter your own answer, then I will accept it.
Nov 12, 2023 at 20:15 answer added Neil Strickland timeline score: 8
Nov 12, 2023 at 19:51 comment added Maxime Ramzi Oh, right, shouldn't that answer the question completely ? Namely the equivalence of KU-modules between the two is classified by the Bott element, and this lifts to a strct element by ""Snaith", so the equivalence lifts to an E_oo-equivalence ?
Nov 12, 2023 at 19:47 comment added Maxime Ramzi Snaith's theorem implies that the Bott element is a strict element, right ? I mean it's much more elementary than Snaith I guess, it's essentially the inclusion from Picard into the semiring of finite dimensional C-vector spaces (topologized).
Nov 12, 2023 at 19:08 comment added Neil Strickland @MaximeRamzi Yes, I think my question is at least closely related to the question of whether the Bott element is a strict unit in $KU$. I guess you are referring to Theorem H of "The chromatic nullstellensatz" which implies that the strict unit spectrum of a suitable algebraic extension of $KU^\wedge_p$ is $\Sigma^2\mathbb{Z}_p\oplus\overline{\mathbb{F}_p}^\times$. The question is whether there is a corresponding $\Sigma^2\mathbb{Z}$ in the strict unit spectrum of $KU$ itself.
Nov 12, 2023 at 18:42 comment added Maxime Ramzi The computation of strict units of E in the Nullstellensatz paper also suggests that there is some interesting commutative algebra map $KU[S^1] \to KU^{S^1}$, at least up to p-completion and going to $KU^{nr}$
Nov 12, 2023 at 15:36 comment added Shay Ben Moshe A small remark is that the $p$-adic case is at least somewhat related to the chromatic Fourier transform, as in Hopkins-Lurie Ambidexterity Corollary 5.3.26 or Barthel-Carmeli-Schlank-Yanovski Theorem A/Theorem D. I didn't think this through and don't see immediately how to connect them.
Nov 12, 2023 at 14:45 history asked Neil Strickland CC BY-SA 4.0