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Nov 11, 2023 at 3:28 comment added GH from MO Very nice argument. It also follows along these lines that $R^\times$ is generated by $\mathbb{C}^\times$ and the exhibited units $\eta_j$. Indeed, the divisors $\mathrm{div}(\eta_j)$ generate an index $3$ subgroup in the group of degree zero divisors supported on $\{P,Q,R\}$, with cosets being represented by the divisors $0$, $Q-R$, $R-Q$. However, $Q\not\sim R$, whence the subgroup in question is the group of all principal divisors supported on $\{P,Q,R\}$. This also shows that $\mathrm{Pic}(\tilde E,S)$ in my post is isomorphic to $\mathbb{Z}\times(\mathbb{Z}/3)$.
S Nov 10, 2023 at 19:05 review First answers
Nov 10, 2023 at 19:18
S Nov 10, 2023 at 19:05 history answered user516477 CC BY-SA 4.0