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Dec 4, 2023 at 18:31 vote accept Drew Brady
Dec 1, 2023 at 23:17 answer added icecuber timeline score: 3
Nov 10, 2023 at 4:01 comment added Drew Brady Of course, one can also drop the constraint $\sum_i b_i^2 \leq 1$, which leads to an upper bound of $t (\max_i a_i)$.
Nov 10, 2023 at 3:59 comment added Drew Brady That approach leads to an upper bound of $\sqrt{\sum a_i^2}$. It is not sharp unless $\sum_i \sqrt{a_i} \leq t \sqrt[4]{\sum_i a_i^2}$. There are vectors that do not satisfy this inequality when $1 < t < d^{3/4}$.
Nov 10, 2023 at 3:11 comment added Thomas Kojar If you drop the square-root-constraint in terms $t$, then you basically have a inequality matrix constraint $$\sum b_{i}^{2}=bIb\leq 1,$$ for the identity matrix $I$, which is standard in textbooks in nonlinear programing like the one by Boyd and Vandenberghe web.stanford.edu/~boyd/cvxbook/bv_cvxbook.pdf. So this less-constrained optimization problem can give you an upper bound.
Nov 10, 2023 at 3:06 comment added Thomas Kojar Are you looking for any particular bounds for some problem? Lower bounds are much easier because you just have to make choices that satisfy the constraints eg. setting $b_{1}=1$ and the rest $b_{i}=0$ and to get a lower bound by $a_{1}$.
Nov 10, 2023 at 2:42 history edited Drew Brady CC BY-SA 4.0
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Nov 10, 2023 at 1:03 comment added Drew Brady This doesn't really seem to help too much. The dual problem is somewhat challenging to handle as well.
Nov 10, 2023 at 1:00 comment added Thomas Kojar I would also try solving the penalized unconstrained version i.e. $$max \sum a_i b_i+c\min(0,1-\sum b_i^2)+c\min(0,t-\sum \sqrt{b_i})$$ and then taking $c\to +\infty$. (see penalized version with inequality constraints in warin.ca/ressources/books/…).
Nov 10, 2023 at 0:50 comment added Thomas Kojar did you try the KKT-conditions and duality? Duality at least gives an upper bound.
Nov 10, 2023 at 0:41 comment added Drew Brady Comment: Of course for such upper and lower bounds, one can simply take $f_t$. I am hoping for something more explicit. (I realize this is loosely formulated, so I leave it open to interpretation and will accept anything that is more explicit than the current variational representation.)
Nov 10, 2023 at 0:39 history asked Drew Brady CC BY-SA 4.0