Timeline for Function orthogonal to $|y-x|$ on $[0,1]$ for every $y \in [0,1]$?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Nov 9, 2023 at 19:03 | comment | added | anonymous_coward | Excellent, that does it. Thanks! | |
| Nov 9, 2023 at 18:03 | comment | added | Iosif Pinelis | @mathworker21 : Since $|0-x|+|1-x|=1$ for all $x\in[0,1]$, we have $\int_0^1 f=0$, so that $f\in L^1$. | |
| Nov 9, 2023 at 17:23 | comment | added | mathworker21 | I didn't really read or think about the problem, but why are you assuming $f \in L^1$? You say the integral may not exist otherwise, but so? | |
| Nov 9, 2023 at 17:22 | history | answered | Aleksei Kulikov | CC BY-SA 4.0 |