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when toggle format what by license comment
Nov 12, 2010 at 20:00 comment added Amit Kumar Gupta Yeah, that's what I meant; fixed it.
Nov 12, 2010 at 19:59 history edited Amit Kumar Gupta CC BY-SA 2.5
edited body
Nov 12, 2010 at 13:26 comment added Joel David Hamkins I think it is more relevant to calculate $(x_1\wedge x_2)\wedge(y_1\wedge y_2)=0$ in your proof, since it is $x_1\wedge x_2$ that is in $A_1\wedge A_2$, etc. (although I understand the expressions are equivalent).
Nov 12, 2010 at 10:26 history answered Amit Kumar Gupta CC BY-SA 2.5