Timeline for Can this system of equations about Newton's formula have concrete result?
Current License: CC BY-SA 4.0
15 events
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Nov 12, 2023 at 5:53 | vote | accept | Er Bu | ||
Nov 7, 2023 at 19:04 | comment | added | paul garrett | Btw, really it should be Girard-Newton formulas, to give credit where credit is due. :) | |
Nov 7, 2023 at 15:56 | answer | added | loup blanc | timeline score: 0 | |
Nov 6, 2023 at 22:21 | history | became hot network question | |||
Nov 6, 2023 at 17:33 | answer | added | Peter Mueller | timeline score: 9 | |
Nov 6, 2023 at 16:36 | history | edited | Michael Hardy | CC BY-SA 4.0 |
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Nov 6, 2023 at 15:39 | comment | added | joro | I think if $n=3$,$S_4$ doesn't have solutions for all algebraic $a$, only for $a$ root of $a^4 - 6*a^3 + 11*a^2 - 6*a=0$. | |
Nov 6, 2023 at 15:01 | comment | added | Federico Poloni | I have seen the definition, but still I think there is something wrong in the formula for $\sigma_n$. For instance, how many factors are there in the numerator if $a$ is not a positive integer? Say, $a=-1$ or $a = 1+i$? | |
Nov 6, 2023 at 14:48 | comment | added | Er Bu | Sorry, maybe I don't give a clear definition of $\sigma_i$ | |
Nov 6, 2023 at 14:43 | history | edited | Er Bu | CC BY-SA 4.0 |
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Nov 6, 2023 at 14:38 | history | edited | Er Bu | CC BY-SA 4.0 |
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Nov 6, 2023 at 14:33 | history | edited | Er Bu | CC BY-SA 4.0 |
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Nov 6, 2023 at 14:33 | comment | added | Federico Poloni | Are you sure about the formula for $\sigma_n$? Shouldn't the first factor be $a$, too? | |
S Nov 6, 2023 at 14:20 | review | First questions | |||
Nov 6, 2023 at 15:43 | |||||
S Nov 6, 2023 at 14:20 | history | asked | Er Bu | CC BY-SA 4.0 |