Timeline for Let $(a_n)_{n\in N}=(1,2,3,4,6,8,9,12,\cdots)$ list the set$\{2^n3^m\mid m,n\in N\}$. Find $α$ such that $(a_n)\alpha\pmod1$ is not equidistributed
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 9, 2023 at 10:32 | comment | added | R.P. | +1. I think any question that gets a follow-up question by a 100k rep user deserves more upvotes. | |
| Nov 5, 2023 at 20:13 | answer | added | Oscar Lanzi | timeline score: 3 | |
| Nov 5, 2023 at 18:58 | vote | accept | Miranda | ||
| Nov 5, 2023 at 18:28 | answer | added | Will Sawin | timeline score: 9 | |
| Nov 5, 2023 at 17:20 | comment | added | Miranda | @Wojowu I'm pretty confident that such a number exists, because no theorem guarantees that $(a_{n}) \alpha$ must be equidistributed, we only know that $(a_{n}) \alpha$ is dense on $[0,1]$. And I think that a number which is normal on a specific base might kill it. | |
| Nov 5, 2023 at 17:12 | comment | added | Wojowu | How confident are you such a number exists? I don't have reason to doubt it but don't know any results which would guarantee it. | |
| Nov 5, 2023 at 17:08 | history | edited | Michael Hardy | CC BY-SA 4.0 |
added 2 characters in body; edited title
|
| Nov 5, 2023 at 16:53 | history | edited | Miranda |
edited tags
|
|
| S Nov 5, 2023 at 16:48 | review | First questions | |||
| Nov 5, 2023 at 19:06 | |||||
| S Nov 5, 2023 at 16:48 | history | asked | Miranda | CC BY-SA 4.0 |