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Nov 8, 2023 at 9:29 comment added SBF Let's say the coupling of $\mu$ and $\nu$ gives almost all the mass to the diagonal with just a little bump under it. They will satisfy the stochastic ordering, but how their neighborhoods will happen to satisfy it as well?
Nov 6, 2023 at 23:03 comment added Jinxiang Yao Yes, I found some references to Infinite Wasserstein Distance, that helped me a lot in understanding its difference with $W_p$, especially their essential difference here whether the strong stochastic order exists. That's really interesting. Many thanks!
Nov 5, 2023 at 13:05 comment added Martin Hairer @JinxiangYao It seems that this distance also goes under the name of $\infty$-Wasserstein distance which makes sense. This may help when looking for literature.
Nov 4, 2023 at 19:52 vote accept Jinxiang Yao
Nov 4, 2023 at 19:21 comment added Jinxiang Yao Thank you so much! The construction is very interesting! For compactly supported probability measure, this metric can avoid the explosive growth of support. So, for example, the probability measure $\mu$ supported in [0,1] and $\nu$ supported in [2,3], and their small neighborhood under this metric can meet the strong order requirement.
Nov 4, 2023 at 10:22 history answered Martin Hairer CC BY-SA 4.0