Skip to main content
14 events
when toggle format what by license comment
Nov 8, 2023 at 11:38 comment added Jinxiang Yao My definition is "there exists $\mu$ and $\nu$ and their neighborhood" not any $\mu$ and $\nu$.
Nov 8, 2023 at 7:23 comment added SBF no, it's not. since there will be some measures in a neighborhood of $\mu$ that are not dominated by $\mu$. My point is that your definition per se only seems to work for discrete topology regardless of the order, since in particular it must work for $\nu = \mu$
Nov 7, 2023 at 21:10 comment added Jinxiang Yao Infinite Wasserstein Distance topology is a nontrivial example here.
Nov 7, 2023 at 14:34 comment added SBF isn't it the case that that's the only topology valid in this case then?
Nov 7, 2023 at 14:03 comment added Jinxiang Yao yes, discrete topology is valid for this case
Nov 7, 2023 at 13:30 comment added SBF what if $\mu = \nu$?
Nov 4, 2023 at 19:52 vote accept Jinxiang Yao
Nov 4, 2023 at 18:05 answer added Dieter Kadelka timeline score: 2
Nov 4, 2023 at 10:22 answer added Martin Hairer timeline score: 2
Nov 4, 2023 at 9:25 history edited YCor CC BY-SA 4.0
removed capitals from title
Nov 4, 2023 at 8:55 history edited Daniele Tampieri CC BY-SA 4.0
Fixed typo
Nov 4, 2023 at 4:05 history edited Michael Hardy CC BY-SA 4.0
space between f and d\mu
S Nov 3, 2023 at 23:20 review First questions
Nov 4, 2023 at 8:55
S Nov 3, 2023 at 23:20 history asked Jinxiang Yao CC BY-SA 4.0