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Nov 3, 2023 at 2:57 history edited Duality CC BY-SA 4.0
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Nov 3, 2023 at 2:35 history edited Duality CC BY-SA 4.0
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Nov 3, 2023 at 2:29 history edited Duality CC BY-SA 4.0
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Nov 3, 2023 at 2:00 history edited Duality CC BY-SA 4.0
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Nov 3, 2023 at 1:34 comment added Jeremy Rouse I think you are confusing $\dim_{\mathbb{F}_{2}} {\rm Sha}(E/\mathbb{Q})[2]$ and the $2$-adic valuation of the order of ${\rm Sha}$. For the $n=16$, $p=48$ curve mentioned in your post, a $2$-descent says that the $2$-Selmer group is isomorphic to $(\mathbb{Z}/2\mathbb{Z})^{4}$.
Nov 2, 2023 at 21:51 history edited Michael Hardy CC BY-SA 4.0
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Nov 2, 2023 at 17:15 comment added Chris Wuthrich For $E$ without rational $2$-torsion, I would look for examples among those curves for which the $2$-torsion of the class number of $\mathbb{Q}(E[2])$ is large.
Nov 2, 2023 at 16:19 comment added Stanley Yao Xiao Partial answer: the answer is no if $E$ has a rational 2-torsion point, which is basically just an application of genus theory. In this case the 2-Selmer rank is bounded explicitly by $2^{\omega(\Delta_E)}$ (up to some fudge factor).
Nov 2, 2023 at 15:34 history asked Duality CC BY-SA 4.0