Skip to main content
11 events
when toggle format what by license comment
Mar 21 at 23:22 answer added wijohns777 timeline score: 1
Oct 31, 2023 at 4:30 history became hot network question
Oct 31, 2023 at 3:16 comment added Willie Wong If you set $y_1 = x_1$, $y_2 = x_2 + x_3$ and $y_3 = x_2 - x_3$, the specific example you asked about can be seen to just be the wave equation (with $y_2$ being the time direction). The fundamental solution of this is well-known, and you can see based on it that a method of characteristics solution is not really possible.
Oct 31, 2023 at 3:12 answer added Willie Wong timeline score: 19
Oct 31, 2023 at 0:55 comment added Deane Yang In general, there is no way to solve a 2nd order PDE in 3 variables using the method of characteristics. If there were, you would have learned about it, and we would not be struggling so much with PDE theory. The question is whether there are examples of 2nd order PDEs in 3 variables that can be solved by such a method, and how does one detect such a PDE.
Oct 30, 2023 at 23:13 comment added Puzzled @ThomasKojar. In the reference you gave there are just examples with first order PDEs.
Oct 30, 2023 at 23:10 comment added Puzzled I added an example to my question to make it more clear.
Oct 30, 2023 at 23:08 history edited Puzzled CC BY-SA 4.0
added 177 characters in body
Oct 30, 2023 at 22:59 comment added Willie Wong To OP: when you say more than two variables to you mean having a domain with more than two dimensions, or having more than 2 unknowns? It is a bit of folklore that method of characteristics is impossible for vector-valued equations in higher dimensions, and similarly for higher order scalar equations in higher dimensions; I'll try to see if I can find a reference or a heuristic argument for you.
Oct 30, 2023 at 21:56 history edited Puzzled CC BY-SA 4.0
edited body
Oct 30, 2023 at 20:30 history asked Puzzled CC BY-SA 4.0