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Oct 29, 2023 at 19:54 comment added Joel David Hamkins Yes, for example, KM+CC is bi-interpretable with ZFC- + there is a largest cardinal, which is inaccessible.
Oct 29, 2023 at 19:47 comment added Zuhair Al-Johar For the record, of course I wanted $\prec$ to be allowed to appear in comprehension. So, here there is a clear benefit gained in that it would enable CC. And you said it enables many bi-interpretation results.
Oct 29, 2023 at 19:45 vote accept Zuhair Al-Johar
Oct 29, 2023 at 19:40 comment added Joel David Hamkins No, because every model of KM can be reduced to the L of the model, which has a definable well order for its classes.
Oct 29, 2023 at 19:39 comment added Zuhair Al-Johar Would it prove the consistency of KM?
Oct 29, 2023 at 19:37 comment added Joel David Hamkins If the expanded language was allowed to appear in the comprehension scheme, then such a well order relation would enable the proof of CC. So the theory would be strictly stronger than KM and not conservative over it.
Oct 29, 2023 at 19:34 comment added Zuhair Al-Johar Nice! This answer greatly enrich the subject. What I had in mind is the second option, that is we add a new binary relation symbol $\prec$ to the signature of $\sf MK$, then add the axiom schema that $\prec$ is a well order over classes, i.e. an areflexic, transitive, connected and well founded relation over all classes. $\prec$ need not be definable. From this answer a definable well order would be beneficial, but would an indefinable one be too?
Oct 29, 2023 at 18:56 history edited Joel David Hamkins CC BY-SA 4.0
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Oct 29, 2023 at 18:44 history edited Joel David Hamkins CC BY-SA 4.0
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Oct 29, 2023 at 18:30 history answered Joel David Hamkins CC BY-SA 4.0