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Timeline for Iterated quotients in GIT

Current License: CC BY-SA 4.0

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Oct 30, 2023 at 9:07 comment added Friedrich Knop Doesn't this follow simply from $(A^N)^{G/N}=A^G$ for invariants?
Oct 30, 2023 at 0:26 history edited John Klein CC BY-SA 4.0
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Oct 29, 2023 at 21:55 history edited John Klein CC BY-SA 4.0
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Oct 29, 2023 at 18:20 comment added John Klein I have edited the question. Thanks.
Oct 29, 2023 at 18:20 history edited John Klein CC BY-SA 4.0
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Oct 29, 2023 at 17:09 comment added LSpice I'm confused about your condition. You seem just to be assuming that $G$ is an extension of $T$ by a finite, commutative group, which is either automatically reductive if you don't assume that reductive groups are connected (and then do we know that $X//G$ exists?), or never reductive unless $G$ equals $T$. In either case, what's the point of invoking reductivity? \\ See also Supposed generalization of $X/(G \times H)\simeq (X/G)/H$ for GIT-quotients.
Oct 29, 2023 at 16:59 history edited John Klein CC BY-SA 4.0
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Oct 29, 2023 at 16:30 history asked John Klein CC BY-SA 4.0