Timeline for Iterated quotients in GIT
Current License: CC BY-SA 4.0
8 events
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Oct 30, 2023 at 9:07 | comment | added | Friedrich Knop | Doesn't this follow simply from $(A^N)^{G/N}=A^G$ for invariants? | |
Oct 30, 2023 at 0:26 | history | edited | John Klein | CC BY-SA 4.0 |
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Oct 29, 2023 at 21:55 | history | edited | John Klein | CC BY-SA 4.0 |
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Oct 29, 2023 at 18:20 | comment | added | John Klein | I have edited the question. Thanks. | |
Oct 29, 2023 at 18:20 | history | edited | John Klein | CC BY-SA 4.0 |
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Oct 29, 2023 at 17:09 | comment | added | LSpice | I'm confused about your condition. You seem just to be assuming that $G$ is an extension of $T$ by a finite, commutative group, which is either automatically reductive if you don't assume that reductive groups are connected (and then do we know that $X//G$ exists?), or never reductive unless $G$ equals $T$. In either case, what's the point of invoking reductivity? \\ See also Supposed generalization of $X/(G \times H)\simeq (X/G)/H$ for GIT-quotients. | |
Oct 29, 2023 at 16:59 | history | edited | John Klein | CC BY-SA 4.0 |
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Oct 29, 2023 at 16:30 | history | asked | John Klein | CC BY-SA 4.0 |