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Oct 26, 2023 at 23:58 history became hot network question
Oct 26, 2023 at 16:55 vote accept Jingeon An-Lacroix
Oct 26, 2023 at 16:50 answer added Piero D'Ancona timeline score: 5
Oct 26, 2023 at 16:20 answer added Bazin timeline score: 3
Oct 26, 2023 at 16:15 comment added Christian Remling One easy test (that suffices for the non-local operators you mentioned) is that the multiplier must be holomorphic because a local operator will send compactly supported functions to compactly supported functions again, and these have holomorphic Fourier transforms.
Oct 26, 2023 at 15:54 history asked Jingeon An-Lacroix CC BY-SA 4.0