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Oct 25, 2023 at 7:32 comment added username @NoamD.Elkies Of course, silly me, thank you!
Oct 25, 2023 at 5:52 comment added Noam D. Elkies The eigenvalues are all integers, so consecutive distinct eigenvalues differ by at least 1 (but for $d>2$ there are huge degeneracies and even for $d=2$ there are eigenvalues of arbitrarily high multiplicity).
Oct 24, 2023 at 20:17 history asked username CC BY-SA 4.0