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Oct 26, 2023 at 19:03 comment added Joe Thanks all for your replies! Yes, in my post I meant W(r) to be the derivative of Brownian motion.
Oct 24, 2023 at 23:12 comment added user479223 Do you mean $W(r)$ to be Brownian motion or the derivative of Brownian motion?
Oct 24, 2023 at 23:04 comment added user479223 There is no issue here. $W(r)$ is just some continuous function so this can be understood pathwise as an ODE.
Oct 24, 2023 at 18:58 history edited Daniele Tampieri CC BY-SA 4.0
Minor Math Jaxing
Oct 24, 2023 at 18:44 history edited YCor CC BY-SA 4.0
formatting, added tag
Oct 24, 2023 at 16:48 answer added Thomas Kojar timeline score: 2
Oct 24, 2023 at 16:46 comment added Thomas Kojar One interpretation can be by letting $X=\frac{dT}{dt}$ and so the Itô formulation is $$dX=(t-A)(t-B)dt+(t-A)(t-B)dB_{t},$$ which is a linear SDE.
S Oct 24, 2023 at 16:25 review First questions
Oct 24, 2023 at 18:58
S Oct 24, 2023 at 16:25 history asked Joe CC BY-SA 4.0