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Oct 20, 2023 at 15:47 comment added Bastam Tajik Well, true that if the two topologies do not match then the Alexandrov topology is not Hausdorff. But "not being Hausdorff", doesn't mean that the two points are indistinguishable. There are weaker versions of distinguishability. I want the two points to share the same neighbourhood filter under Alexandrov topology and have non-equal neighbourhood filters under the manifold topology. Is this possible at all?
Oct 20, 2023 at 5:16 history answered Clemens Sämann CC BY-SA 4.0