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Oct 19, 2023 at 15:06 vote accept Lau
Oct 19, 2023 at 11:23 history edited Stefaan Vaes CC BY-SA 4.0
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Oct 19, 2023 at 9:50 history edited Stefaan Vaes CC BY-SA 4.0
When interpreting "hyperfinite" as arbitrary "approximately finite dimensional", the result may fail and this more extensive answer proves this.
Oct 19, 2023 at 9:08 comment added Stefaan Vaes @Lauritz. I see. In my conventions (but not generally agreed upon), hyperfinite means "finite and approximately finite dimensional (AFD)". I will update my answer, because for certain type III factors the property does not hold.
Oct 19, 2023 at 4:54 comment added Lau Thanks for your answer Stefaan! I'm a bit puzzled by the "unique trace preserving conditional expectation" that you mention. I only understand this if the factor $R$ is also finite.
Oct 18, 2023 at 16:59 history answered Stefaan Vaes CC BY-SA 4.0