Timeline for Number of atoms of a probability measure
Current License: CC BY-SA 4.0
4 events
when toggle format | what | by | license | comment | |
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Oct 14, 2023 at 19:28 | comment | added | Julian Newman | Replacing $\mu\Big(\Big[\frac{j}{k},\frac{j+1}{k}\Big)\Big)^{\!\epsilon}$ with $\, \mathbf{1}_{[\epsilon,\infty)}\!\!\left(\mu\Big(\Big[\frac{j}{k},\frac{j+1}{k}\Big)\Big)\right)$ should make it work. | |
Oct 14, 2023 at 18:35 | comment | added | Christian Remling | If $d\mu = \chi_{(0,1)}\, dx$, then the sum equals $k^{1-\epsilon}$, so the first limit is already $=\infty$. | |
Oct 14, 2023 at 18:06 | review | Low quality posts | |||
Oct 14, 2023 at 19:38 | |||||
Oct 14, 2023 at 17:43 | history | answered | Anthony Quas | CC BY-SA 4.0 |