Timeline for Conjecture on A057030
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 16, 2023 at 12:16 | comment | added | Notamathematician | Thank you for edit! Note that I'm not a mathematician, just an experimenter with random changes in some already known natural formulas. | |
| Oct 16, 2023 at 12:00 | vote | accept | Notamathematician | ||
| Oct 16, 2023 at 9:14 | comment | added | Ilya Bogdanov | I've expanded that; but I did not think this is that hard. | |
| Oct 16, 2023 at 9:14 | history | edited | Ilya Bogdanov | CC BY-SA 4.0 |
added 563 characters in body
|
| Oct 16, 2023 at 8:45 | comment | added | Notamathematician | I have no problem checking that $c(n,m)$ is working correctly. I wonder how you derive it. Why we have $c(0,m)=2m-1$? Why $c(n,m)$ has exactly this form? | |
| Oct 15, 2023 at 16:19 | comment | added | Ilya Bogdanov | You may check what happens if you apply the reverse process to your numbers (5, 10, 15) if you wish/ fe.g. Toy will get $5\to 9\to 10\to 10\to 11\to 11$. Please indicate which part is incomprehensible for you. | |
| Oct 15, 2023 at 13:19 | comment | added | Notamathematician | Sorry, I didn't get it anyway (so I can't accept the answer). Perhaps if you add more details and give examples, I will be able to figure it out. | |
| Oct 15, 2023 at 13:03 | comment | added | Ilya Bogdanov | Well, it's a standard formula for the reflection. If you revert the segment $\{0,1,\dots,m-n-1\}$, the number $i$ swaps with $m-n-i$. | |
| Oct 15, 2023 at 10:00 | comment | added | Notamathematician | Thank you for answer! Could you clarify why $c(n,m)$ has exactly this form? | |
| Oct 14, 2023 at 13:26 | history | answered | Ilya Bogdanov | CC BY-SA 4.0 |