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Oct 15, 2023 at 11:42 vote accept daon
Oct 14, 2023 at 20:45 history became hot network question
Oct 14, 2023 at 19:43 answer added Nate Eldredge timeline score: 1
Oct 14, 2023 at 17:43 answer added Anthony Quas timeline score: 0
Oct 14, 2023 at 17:39 history edited daon CC BY-SA 4.0
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Oct 14, 2023 at 17:09 comment added Gerald Edgar I guess $\mathbb N^\infty$ means $\mathbb N \cup \{\infty\}$.
Oct 14, 2023 at 17:04 comment added Christian Remling Thanks for clarifying. Your first sentence seems slightly ambiguous, or at least I misread it as "its" in "with its Borel sets" referring to $PR$ rather then $\mathbb R$.
Oct 14, 2023 at 14:00 comment added daon The $\sigma$-algebra is the smallest one making $\mu \mapsto \mu(U)$ measurable for every Borel set $U$.
Oct 14, 2023 at 10:14 history asked daon CC BY-SA 4.0