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Oct 12, 2023 at 14:37 comment added 351910953 Thanks for the helpful comments. @Johan Do you know whether this is written down somewhere?
Oct 11, 2023 at 19:00 comment added Johan You can make this work with crystalline cohomology of abelian schemes in char 0. Essentially you just have to show that the Kodaira-Spencer map is the same as whet you get from the hodge filtration thing. It is easier than the char p case (especially if you first prove the thing for p-divisible groups which is quite a bit harder as you have to prove unobstructedness first).
Oct 11, 2023 at 0:05 comment added Will Sawin I think one needs to use not just algebraic de Rham cohomology but its isomorphism with singular cohomology for this.
Oct 10, 2023 at 23:59 history asked 351910953 CC BY-SA 4.0