Timeline for If $F$ is a prosoluble subgroup of a free profinite product $\amalg G_i$ and $F \cap G_i^g$ is pro-$p$, is also $F$ pro-$p$?
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
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| Feb 20 at 18:31 | vote | accept | Lucas | ||
| Feb 19 at 14:16 | comment | added | YCor | Note that the question is asked in the positive in the title and in the negative in the body. Maybe in the body it should match the title and hence ask whether every $F$ as in (i) is pro-$p$. | |
| Feb 19 at 13:50 | answer | added | Dan Haran | timeline score: 2 | |
| Oct 8, 2023 at 22:04 | history | edited | YCor | CC BY-SA 4.0 |
made corrections given by OP in comments
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| Oct 8, 2023 at 20:27 | comment | added | Lucas | @YCor the original statement says that there exists $i$ and $g \in G$ ($G$ is the free product) such that $F^g \subset G_i$. | |
| Oct 8, 2023 at 20:26 | comment | added | Lucas | @YCor the paper is: link.springer.com/article/10.1007/BF02567982 | |
| Oct 8, 2023 at 18:50 | comment | added | YCor | Could you provide the reference? Also in (iii) "A conjugate" is unclear. Better write "Some conjugate" or "Every conjugate". | |
| Oct 8, 2023 at 16:23 | history | edited | Lucas | CC BY-SA 4.0 |
edited title
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| Oct 8, 2023 at 16:23 | comment | added | Lucas | @HJRW of course. It was a careless mistake. | |
| Oct 8, 2023 at 15:58 | comment | added | HJRW | Isn’t it more usual to use $\coprod$ for a (profinite) free product? | |
| Oct 8, 2023 at 15:23 | history | edited | Lucas | CC BY-SA 4.0 |
deleted 1 character in body
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| Oct 8, 2023 at 2:37 | history | asked | Lucas | CC BY-SA 4.0 |