Timeline for How many integrals can give multiples of $\pi$?
Current License: CC BY-SA 4.0
11 events
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| Oct 6, 2023 at 16:59 | comment | added | Steven Stadnicki | I'm still curious as to whether there's an answer with $q()$ irreducible but this absolutely answers the question I had. Thank you! | |
| Oct 6, 2023 at 16:58 | vote | accept | Steven Stadnicki | ||
| Oct 5, 2023 at 16:34 | comment | added | Steven Stadnicki | I should have clarified degree $\lt n$; thank you! I was thinking that any polynomials of degree higher than $q$ would yield a polynomial quotient that integrated to a rational value, but forgot that that rational value can be zero; more broadly, if $\int_0^1\frac{p(x)}{q(x)}\in\mathbb{Q}\pi$ then so is $\int_0^1\frac{p(x)+z(x)q(x)}{q(x)}$ for any $z(x)$ with $\int_0^1z(x)=0$. | |
| Oct 5, 2023 at 14:35 | history | edited | Robert Israel | CC BY-SA 4.0 |
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| Oct 5, 2023 at 14:06 | history | edited | Robert Israel | CC BY-SA 4.0 |
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| Oct 5, 2023 at 0:39 | history | edited | Robert Israel | CC BY-SA 4.0 |
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| Oct 5, 2023 at 0:22 | history | undeleted | Robert Israel | ||
| Oct 5, 2023 at 0:22 | history | edited | Robert Israel | CC BY-SA 4.0 |
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| Oct 5, 2023 at 0:18 | history | deleted | Robert Israel | via Vote | |
| Oct 5, 2023 at 0:15 | history | edited | Robert Israel | CC BY-SA 4.0 |
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| Oct 5, 2023 at 0:09 | history | answered | Robert Israel | CC BY-SA 4.0 |