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Timeline for Root system terminology

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Oct 4, 2023 at 12:51 history edited RobPratt
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Oct 4, 2023 at 8:46 history edited YCor
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Oct 4, 2023 at 0:09 comment added LSpice Re, excellent! If you're interested beyond the reductive case, it is discussed in Section 3.3 of Conrad, Gabber, and Prasad - Pseudo-reductive groups. Just to have the other link here, as you certainly know, it's Borel - Linear algebraic groups.
Oct 3, 2023 at 23:57 comment added Eric @LSpice: Ah, that's nice! I had included a proof since I didn't know a reference, but that shortens my paper by a page.
Oct 3, 2023 at 23:17 comment added LSpice Re, if you're just looking for such a theorem, then the condition with rational $c$ can be weakened just to integral $c$, and it is Proposition 21.9(ii) of Borel.
Oct 3, 2023 at 21:14 comment added Eric @Lspice: Yes, that does sound like what these probably are. What's useful about them for me is that if $\Phi$ is the (relative) root system of a reductive algebraic group, then my condition ensures that the group generated by the root subgroups corresponding to elements of $\Phi'$ is a unipotent subgroup that can be decomposed as the set-theoretic product of the root subgroups associated to the non-divisible elements of $\Phi'$. Mostly I want to make sure that there isn't a standard name for these, since otherwise I'll look like an idiot if I make one up.
Oct 3, 2023 at 20:35 comment added LSpice I suspect (still assuming $c$s are integers) that $\Phi'$ arises as follows: replace $\Phi$ by a closed subsystem, take a set of positive roots, and then take the complement of a further closed subsystem. But I'm not certain. (Oh, and I just saw your response. Then probably, instead of closed, take "Levi" (intersection of two opposite parabolic subsets).)
Oct 3, 2023 at 20:27 comment added Eric @LSpice: They are arbitrary rationals. I'm also not assuming that my root system is reduced, so it's possible that for a root $\lambda$ the element $\frac{1}{2}\lambda$ is also a root.
Oct 3, 2023 at 20:25 comment added LSpice @SamHopkins, as you doubtless know, if the $c$s are integers, then (1) is equivalent to being closed.
Oct 3, 2023 at 20:24 comment added Sam Hopkins A subset $C \subseteq \Phi$ is called closed if $\alpha, \beta \in C$ and $\alpha+\beta \in \Phi$ imply $\alpha+\beta \in C$. Not exactly the same as your conditions, but this is an important notion which has been studied a lot.
Oct 3, 2023 at 20:24 comment added LSpice This condition seems natural, though I don't know a term; but, to clarify, are your $c$s integers, or arbitrary rationals?
Oct 3, 2023 at 20:22 history edited Eric CC BY-SA 4.0
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S Oct 3, 2023 at 20:21 review First questions
Oct 3, 2023 at 20:56
S Oct 3, 2023 at 20:21 history asked Eric CC BY-SA 4.0