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Oct 12, 2023 at 21:17 comment added Daniel Asimov Good point, this is a natural way to derive the result. And I can compute the curvature of the graph of a function. But I was surprised at the complexity of the expression for the gaussian curvature of a parametric Riemann surface embedded in ℂ^2 locally via z |—> (f(z), g(z)), where f and g are entire functions, say.
Sep 30, 2023 at 6:40 history answered David Lehavi CC BY-SA 4.0