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Oct 2, 2023 at 4:13 vote accept Ribhu
Sep 28, 2023 at 10:46 history edited Iosif Pinelis CC BY-SA 4.0
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Sep 28, 2023 at 3:46 history edited Iosif Pinelis CC BY-SA 4.0
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Sep 28, 2023 at 3:36 comment added Iosif Pinelis @Ribhu : The inequality in your comment is not homogeneous in the $X_i$'s. On the other hand, the inequality $L\le R$ in my answer seems to be the right one.
Sep 28, 2023 at 3:30 comment added Ribhu Also, I think in your example, the inequality should read as $\|\sum_{1}^n X^2_i\|_{p/2}\le (\sum_{1}^n \|X_i\|^2_p)^{1/2}$
Sep 28, 2023 at 3:00 history answered Iosif Pinelis CC BY-SA 4.0