Timeline for Existence of tensor product of subalgebras
Current License: CC BY-SA 2.5
4 events
when toggle format | what | by | license | comment | |
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Nov 13, 2010 at 2:59 | comment | added | Martin Argerami | If $\mathcal{A}$ has the same unit as $\mathcal{G}$, then yes. | |
Nov 11, 2010 at 2:19 | comment | added | kett | so you are saying the fact that $\mathcal{A} \cong \mathbb{M}_d$ is a subalgebra of $\mathcal{G}$ implies $d$ must divide $n$? | |
Nov 10, 2010 at 14:10 | vote | accept | kett | ||
Nov 10, 2010 at 14:10 | |||||
Nov 10, 2010 at 9:38 | history | answered | Bugs Bunny | CC BY-SA 2.5 |