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Sep 26, 2023 at 23:03 comment added LSpice You referred to the "barr construction". I know that there's a Michael Barr whose work is not disjoint from this topic, but I think you meant the bar construction, and edited accordingly. I hope that was correct.
Sep 26, 2023 at 23:02 history edited LSpice CC BY-SA 4.0
barr -> bar; consistency in n-category vs. $n$-category
Sep 26, 2023 at 18:31 vote accept Brendan Murphy
Sep 26, 2023 at 14:16 history edited Simon Henry CC BY-SA 4.0
added 258 characters in body
Sep 26, 2023 at 14:14 comment added Simon Henry @Mike maybe you are right. I was thinking about it in the sense of giving category theoretic meaning to the question of whether "a given weak n-category can be represented by a strict n-category", which at first sight looks like a non-CT problem but can be phrased in terms of existence of a certain filtration on the object (or maybe as well in terms of vanishing of certain higher order operation?). I edited to try to clarify that point.
Sep 26, 2023 at 6:51 history edited Mike Shulman CC BY-SA 4.0
Added mention of dssi's to (B).
Sep 26, 2023 at 3:22 comment added Mike Shulman But then in what sense is your description of strict $n$-categories "about categories"?
Sep 26, 2023 at 2:55 comment added Simon Henry @MikeShulman, I Agree, but that's somehow what I mean when I say "it is not a result about categories anymore". For e.g. when you phrase Arlin's work in these terms then what he is considering is a pair of a set valued functor and a cat valued functor with a level-wise essentially surjectif functor, and most of what he is doing - or at least the key steps - revolves around the set valued functor, and not the cat valued functor.
Sep 26, 2023 at 2:06 comment added Mike Shulman On the other hand, if you're willing to admit your description of strict $n$-categories as valid, then for $n=1$ it gives you a notion of strict category, and basically any non-equivalence-invariant notion you like can be formulated in terms of those. For instance, an Arlin prederivator could be defined as a 2-functor taking values in strict categories.
Sep 26, 2023 at 2:02 history edited Simon Henry CC BY-SA 4.0
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Sep 26, 2023 at 2:01 comment added LSpice I got a bit confused about numbering, and so didn't want to edit for fear of disrupting meaning, but did you really mean to refer to "the second second example"?
Sep 26, 2023 at 2:00 history edited LSpice CC BY-SA 4.0
Proofreading
Sep 26, 2023 at 1:53 history edited Simon Henry CC BY-SA 4.0
added 739 characters in body
Sep 26, 2023 at 0:56 comment added Mike Shulman For another example of (B), how about lax functors between bicategories, which are not invariant under equivalence of bicategories (or even 2-equivalence of 2-categories)? (Of course one may claim they are "really" about double categories instead...)
Sep 26, 2023 at 0:55 comment added Mike Shulman Interesting point about Arlin's work; that's a good explanation of why it always made me uncomfortable, more so than your examples of (A).
Sep 26, 2023 at 0:52 comment added Mike Shulman However, the matching up of the source and target in composition is not an issue with the principle of equivalence, because when the definition is stated correctly using a family of hom-sets indexed by the objects, there is no equality of objects mentioned.
Sep 25, 2023 at 19:50 comment added Simon Henry In a sense yes. When we say "a category is a set of object together with..." we break the equivalence principle, as the set of objects is not an invariant under equivalence. See here mathoverflow.net/q/309524 and once you take the step of saying that a category is "a groupoid of objects together with..." then you have to contend with the issue you mention seriously
Sep 25, 2023 at 19:50 history edited LSpice CC BY-SA 4.0
Proofreading and names of links
Sep 25, 2023 at 19:44 comment added Will Sawin Do the strictness problems you mention for higher categories also show up to some extent for 1-categories? Like the notion of composition as a function on pairs of morphisms with the same source and target is strict because we demand the source and target are equal on the nose and not just isomorphic.
Sep 25, 2023 at 19:22 history made wiki Post Made Community Wiki by Stefan Kohl
Sep 24, 2023 at 3:22 history answered Simon Henry CC BY-SA 4.0