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Timeline for Does this expression always vanish?

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Sep 24, 2023 at 23:10 comment added Michael Engelhardt @quarta - no, it's not that simple. The product is not symmetric under exchange of $i$ and $j$.
Sep 24, 2023 at 20:08 comment converted from answer quarta This is a comment, not an answer but I am not entitled. By exchanging $i$ and $j$ one sees that each term in the double sum occurs twice, with alternating sign.
Sep 24, 2023 at 3:14 vote accept Silly Point
Sep 24, 2023 at 3:13 vote accept Silly Point
Sep 24, 2023 at 3:14
Sep 23, 2023 at 12:29 history became hot network question
Sep 23, 2023 at 9:24 answer added Ilya Bogdanov timeline score: 35
Sep 23, 2023 at 8:46 comment added Per Alexandersson There should be some symmetric function identity hiding here.
Sep 23, 2023 at 6:59 comment added T. Amdeberhan It seems equivalent to \begin{align} \sum_{i=1}^N\sum_{j=1\\ j\ne i}^N\frac{A_i+A_j}{A_i-A_j}\prod_{k=1\\ k\ne i}^N\frac{A_i A_k}{(A_i-A_k)^2}=0. \end{align}
Sep 23, 2023 at 6:46 comment added Greg Martin Other observations: the expression can be written as $$(A_1\cdots A_n) \sum_{1\le i<j\le n} \frac{A_i+A_j}{(A_i-A_j)^3} \biggl( A_i^{n-2} \prod_{\substack{1\le k\le N\\k\ne i\\k\ne j}}\frac1{(A_i-A_k)^2} - A_j^{n-2} \prod_{\substack{1\le k\le N\\k\ne i\\k\ne j}}\frac1{(A_j-A_k)^2} \biggr).$$This makes it easy to see that the order of the pole at any $A_i=A_j$ is at most $2$ (multiplying through by $(A_i-A_j)^3$ and setting $A_i=A_j$ yields $0$).
Sep 23, 2023 at 6:41 comment added Carlo Beenakker as a simple test, if I set $A_i=i$ for all $i$, the expression can be evaluated in closed form and gives 0.
Sep 23, 2023 at 4:54 comment added David Roberts On MathOverflow, question titles that are commands (like "Prove that...") give the impression that the original source is a homework or textbook question. It's best to phrase the title as an actual question, not something that gives the impression you know the answer and you're challenging users here.
Sep 23, 2023 at 4:52 history edited David Roberts CC BY-SA 4.0
removed imperative tense from title
S Sep 23, 2023 at 4:26 review First questions
Sep 23, 2023 at 5:57
S Sep 23, 2023 at 4:26 history asked Silly Point CC BY-SA 4.0